Evaluate.
1. $\displaystyle \lim_{x \to \--2} \frac{x + 4}{x + 3} = 2$
2. $\displaystyle \lim_{x \to \--2} \frac{x^2 + x - 2}{x^2 + 5x + 6} = -3$
3. $\displaystyle \lim_{x \to \-2}$ $\displaystyle \frac {\sqrt {(x-1)} - 1}{(x - 2)} = 0.5$
4. $\displaystyle \lim_{x \to \-1} \frac{x - 1}{x^2 - 1} = 0.5$
Are my answers correct?