Thread: Domain Logarithmic Function (Unsolved)

f(x)=-2ln(x+1)

Find the domain of f.

So, far this is I have:
f(x)=-2ln(x+1)
f(x)=-2e^(x+1)

Can anyone go over this problem step by step with me?

for ...the only problem is that due to s properties...so

Originally Posted by wickwiki

f(x)=-2ln(x+1)

Find the domain of f.

So, far this is I have:
f(x)=-2ln(x+1)
f(x)=-2e^(x+1)

Can anyone go over this problem step by step with me?

The domain of



is the set

so your function is related to the unshifted natrual log by

This shifts the graph one unit left in the x direction so the domain is

Originally Posted by Mathstud28

for ...the only problem is that due to s properties...so

it must be strictly greater than zero. log(0) is undefined as well

I had it that way...but I was thinking of and I went back and changed it...on these forums I try to answer as fast as I can so I get messed up sometimes...thanks!...I knew that by the way =D

Originally Posted by Mathstud28

...I knew that by the way =D

that's ok

yes, i know you knew

::blushes:: haha thanks

OK, solution solved thanks for the help.

I would like to know a bit more about how you solved it.

f(x)=-2ln(x+1)
So, what happens with the negative two exactly?

Because the one of my similar problems I solved ln(x+4) and I got
Domain= (-4,\infty).

So, how is the -2 effect the equation?

The only thing that matters in a is that the domain is restricted so that ...make sense?