Hi,
How do i express this in terms of t?
a dv/dt = -g/b2(v(t)^2 + b^2)
I will give you an example $\displaystyle \frac{dy}{dx}=9y^4$..seperate so that all the $\displaystyle y$s are with the $\displaystyle dy$s and all the $\displaystyle dx$s are with the $\displaystyle x$s...so we have then that $\displaystyle \frac{dy}{y^4}=9dx$...now we want to get rid of the dx's and dy's...so we integrate $\displaystyle \int\frac{dy}{y^4}=\int{9dx}$...so we get $\displaystyle \frac{-1}{3y^3}=9x+C$...now since y is a function of x to we are trying to find y like you are trying to find v...so we solve for y $\displaystyle y^3=\frac{-1}{27x+C_1}$....$\displaystyle y=\frac{-1}{(27x+C_1)^{\frac{1}{3}}}$..now that is an SDE...now reevaluating this...can you tell me if this an SDE?