Q (i)prove that d/dx(artanhx)=1/(1-x^2)

this is just artanhx=y, tanhy=x then diff.

can't do simplify end of (ii) Q by using partial ractions and integrating deduce from this(ans to (i)) the logarithmic form of artanhx,,,i know the log form of artanhx is 1/2ln(1+x/1-x)???????

i did 1/(1-x^2) = (int)-1/(-2x-2) -(int)1/(2x-2)

giving 1/2ln|-2x-2| -ln|2x-2| then i get to 1/2ln|(-2x-2)/(2x-2)| not sure where to go from here i think its easy but im being ignorant,,,the log form of artanhx is 1/2ln(1+x/1-x)???????pls help!!!!