A rectangular storage container with an open top is to have a volume of 10 meters cubed. The length of this base is twice the width. Material for the base costs $10 per square meter. Material for the sides costs $6 per square meter. Find the cost of materials for the cheapest such container.

My work:

The area of the base is given by:

$\displaystyle A_b = 2w^2$

The area of the sides is given by:

$\displaystyle A_s = 4wh$

I know the cost per square meter so:

$\displaystyle C_b = 20w^2$

$\displaystyle C_s = 24wh$

So the total cost is represented by:

$\displaystyle C = 20w^2 + 24wh$

And I know that the volume is equal to 10 cubic meters so:

$\displaystyle V = l\cdot w\cdot h$

$\displaystyle l\cdot w\cdot h = 10$

$\displaystyle 2w^2\cdot h = 10$

$\displaystyle w^2\cdot h = 5$

$\displaystyle h = \frac {5}{w^2}$

I plug that into my cost formula:

$\displaystyle C(w) = 20w^2 + \frac {120}{w}$

Take the derivative:

$\displaystyle C'(w) = 40w - \frac {120}{w^2}$

I find the critical points to be 0, 1.44.

Then I find that the absolute minimum is 1.44 but when I use this number I get the incorrect answer of 124 (ish).

Any suggestions?