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**Ghostrider** Question:

"y1 (t) = 1/√(1-2t) and y2 (t) = 1/√(4-2t) are solutions of dy/dt = y^3. Use the plot of the solutions to answer the following parts of this question: (a) consider the IVP consisting of the differential equation given together with the initial condition y(0)=1. Find the interval of t for which the solution to the IVP exists. (b) What can you say about the behaviour of a solution to this differential equation which has an initial condition satisfying 0.5<y(0)<1.0?"

I've plotted these solutions and uploaded a picture of the graph. Help will be appreciated...thank you