As you done, you can use the limits 0 to Pi/5, then since there is symmetry, you can multiply by 5.
When integrating a , a good identity to use is
So, I've tried this problem about 10 times, and I'm not quite sure what I'm doing wrong.
Find the area inside one leaf of the rose
I know the graph looks like a 5 leaf rose.
I used the equation A= integral (1/2r^2)dθ
Maybe I'm bounding my integral wrong?? I have it from 0 to pi/5
Or maybe my antiderivative is wrong??? I have 4θ - (4/10)(sin10θ)
Any help would be greatly appreciated! This question is really starting to frustrate me!