As you done, you can use the limits 0 to Pi/5, then since there is symmetry, you can multiply by 5.
When integrating a , a good identity to use is
.
So, I've tried this problem about 10 times, and I'm not quite sure what I'm doing wrong.
Find the area inside one leaf of the rose
r= 4sin(5θ)
I know the graph looks like a 5 leaf rose.
I used the equation A= integral (1/2r^2)dθ
Maybe I'm bounding my integral wrong?? I have it from 0 to pi/5
Or maybe my antiderivative is wrong??? I have 4θ - (4/10)(sin10θ)
Any help would be greatly appreciated! This question is really starting to frustrate me!