# im having trouble with this one.

• Apr 4th 2008, 06:24 AM
waite3
im having trouble with this one.
im having some trouble figuring this one out. i would appreciate any help.thanks

An aquarium 8m long, 3m wide, and 3m deep is full of water. Find the following:
the hydrostatic pressure on the bottom of the aquarium
the hydrostatic force on the bottom of the aquarium
and the hydrostatic force on one end of the aquarium
• Apr 4th 2008, 09:24 AM
Aryth
a) The formula for hydrostatic pressure is:

$\displaystyle P = \rho gh$

$\displaystyle \rho = density$

$\displaystyle h = \text{distance below surface}$

We know that:

$\displaystyle \rho_{water} = 1,000 \frac{kg}{m^3}$

$\displaystyle h = 3 m$

$\displaystyle g = 9.8 \frac{m}{s^2}$

Therefore:

$\displaystyle P = 1000*9.8*3$

$\displaystyle P = 29.4 kPa$

b) The formula for Force is:

$\displaystyle F = PA$

The Area of the bottom of the tank is:

$\displaystyle A = length*width = 8 * 3 = 24 m^2$

So:

$\displaystyle F = 29400*24$

$\displaystyle F = 705,600 N$

c) I'll have to do later if no one does it by the time I come back.
• Apr 4th 2008, 10:15 AM
waite3
thanks for your help
nice thanks a lot i figured out number 3 which was 29400/2*9=132300