Find the area enclosed by the polar curve : r = 5 e^(0.7θ) on the interval 0 ≤ θ ≤ [1/8] and the straight line segment between its ends. Please help!
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Originally Posted by Del Find the area enclosed by the polar curve : r = 5 e^(0.7θ) on the interval 0 ≤ θ ≤ [1/8] and the straight line segment between its ends. Does [1/8] mean one eighth of a radian? If so, then $\displaystyle A = \int_0^{1/8}\!\!\int_0^{5e^{0.7\theta}}\!\!\!\!\!\!r\,drd\th eta$. I get the answer to be about 1.7.
I think you are right, but I think I need the answer to 5 decimal places, if you would be so kind.
It's pretty straightforward. Opalg gave you a simplified result, so with 5 decimal places the answer is $\displaystyle 1,70756.$
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