Find the length of the curve. x=3y^(3/4) - (3/32)y^(2/3); -8≤y≤216 L=? thanks for any help
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Originally Posted by waite3 Find the length of the curve. x=3y^(3/4) - (3/32)y^(2/3); -8≤y≤216 L=? thanks for any help are you sure you set up the integral right? $\displaystyle L = \int_{-8}^{216} \sqrt{1 + [x']^2}~dy$
what do you come out with for an answer because my answer is way off
How did you set up the integral? How do you know your answer is way off? Letting us know what you have done so far would be far better than just telling you the answer.
i keep getting 3843 and its not the right answer can anyone help me out thanks
Unless I am missing something here, this integral can only be solved numerically....
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