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Math Help - Funtion bessel

  1. #1
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    Funtion bessel

    Hello to everybody!
    I have a problem with Bessel funtion.
    Can I say that Jo^2(x)=Jo(x)*Jo(x)
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  2. #2
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    If you asking that J_{\mu} ^2 (x) = J_{\mu} (x) J_{\mu}(x) the answer is yes. The same thing with other functions too. For example, \sin^2 x = \sin x \cdot \sin x.
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  3. #3
    Grand Panjandrum
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    Quote Originally Posted by ThePerfectHacker View Post
    If you asking that J_{\mu} ^2 (x) = J_{\mu} (x) J_{\mu}(x) the answer is yes. The same thing with other functions too. For example, \sin^2 x = \sin x \cdot \sin x.
    However it's a notation to be deprecated as it allows ambiguous notation since we also have:

    J_{\mu} ^2 (x) = J_{\mu} (J_{\mu} (x))

    to be encouraged is:

    (J_{\mu} (x))^2 = J_{\mu} (x) J_{\mu}(x)

    The same goes for sin, also I don't like the usage \sin x rather than \sin (x)

    RonL
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  4. #4
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    Quote Originally Posted by CaptainBlank View Post
    J_{\mu} ^2 (x) = J_{\mu} (J_{\mu} (x))
    But this does not make sense. Bessel function's domain is usually positive. While the range is both positive and negative. So when you compose them you get a problem.
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  5. #5
    Grand Panjandrum
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    Quote Originally Posted by ThePerfectHacker View Post
    But this does not make sense. Bessel function's domain is usually positive.
    Why don't you check that, what is usual for one person is not neccessarily so for another.

    RonL
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