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Math Help - Stationary points query

  1. #1
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    Stationary points query

    Find the two stationary ponts of y = 1/3x^3 - 1/2x^2 - 6x?

    Gradient function: = x^2 – x - 6
    -> x^2 - x - 6 = 0

    I do not know where to go from here...
    I have tried this:

    -> (x + 2) (x - 3) = 0
    -> x = -2, 3
    I need to find two stationary points. Do I now substitute -2 into the original to find one set of stationary points and then substitute 3 into the original equation to find the co-ordinates for the second stationary point?

    Thank you in advance.
    Last edited by Jamie88; April 2nd 2008 at 03:29 AM.
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  2. #2
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    Quote Originally Posted by Jamie88 View Post
    Do I now substitute -2 into the original to find one set of stationary points and then substitute 3 into the original equation to find the co-ordinates for the second stationary point?
    Yes you do
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  3. #3
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    Cheers mate.

    I neglected my coursework for a while and forgot a few crucial points lol.
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