Find the two stationary ponts of y = 1/3x^3 - 1/2x^2 - 6x?

Gradient function: ý = x^2 – x - 6

-> x^2 - x - 6 = 0

I do not know where to go from here...

I have tried this:

-> (x + 2) (x - 3) = 0

-> x = -2, 3

I need to find two stationary points. Do I now substitute -2 into the original to find one set of stationary points and then substitute 3 into the original equation to find the co-ordinates for the second stationary point?

Thank you in advance.