int(cuberoot(x^3+1)x^5dx

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- Apr 1st 2008, 05:29 PMsamdmansamintegration by substitution
int(cuberoot(x^3+1)x^5dx

- Apr 1st 2008, 05:32 PMJhevon
- Apr 1st 2008, 05:37 PMsamdmansamInt by substitution
- Apr 1st 2008, 05:39 PMJhevon
- Apr 1st 2008, 05:51 PMKrizalid
Make $\displaystyle z^3=x^3+1\implies z^2\,dz=x^2\,dx,$ it's a more direct way to solve the problem, you get rid of the cube root.

- Apr 1st 2008, 06:45 PMsamdmansamcould you please take it a little further
my text has very basic examples then skips to questions with cuberoots