Don't have any real idea how to go about this one, even thought its probably really easy... thnanks for the help

Find the length of the curve:

x=[3y^(4/3)]-(3/32)y^(2/3)

-27<y<27 (both those are less than or equal to)

thanks

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- Apr 1st 2008, 04:40 PMN736RACurve Lengths
Don't have any real idea how to go about this one, even thought its probably really easy... thnanks for the help

Find the length of the curve:

x=[3y^(4/3)]-(3/32)y^(2/3)

-27<y<27 (both those are less than or equal to)

thanks - Apr 1st 2008, 06:13 PMSoroban
Hello, N736RA!

Quote:

Find the length of the curve: .

We have: . . . . .

Differentiate: .

. . . . . . . .

. . . . . .

. . . .

You must integrate and evaluate: .

- Apr 1st 2008, 07:08 PMN736RA
thanks for the reply! Although, when I do that integral I get 0 (which makes sense), yet the program I'm using tells me that 0 isnt the right answer, any ideas? Edit: nevermind, I figured it out, thanks for your help!