Would anyone be able to help me figure out the integral of x/x-1 dx? The "integral sign" if you will has a 5 at the top and a 2 at the bottom.
please use parentheses!
do you mean $\displaystyle \int_2^5 \frac x{x - 1}~dx$?
if so, you should have typed: x/(x - 1)
anyway, note that $\displaystyle \frac x{x - 1} = \frac {x - 1 + 1}{x - 1} = \frac {x - 1}{x - 1} + \frac 1{x - 1} = 1 + \frac 1{x - 1}$
so, your integral is: $\displaystyle \int_2^5 \left( 1 + \frac 1{x - 1}\right)~dx$
can you continue?
Yup, I think I got! To save myself typing out all the calculations I'll just say I got 3 + ln4 and hope whoever else attempted this did too!
Sorry about the lack of parentheses. Clearly multitasking is not my forte!
Edit: To emphasize that point I forgot to say thank you! So thanks.