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Thread: How would you go about integrating(really sorry if the "LaTex" is wrong.

  1. #1
    MHF Contributor Mathstud28's Avatar
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    How would you go about integrating(really sorry if the "LaTex" is wrong.

    $\displaystyle \int {\frac{\1}{\sqrt{\lnx}}}\,dx}$ ?
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  2. #2
    Bar0n janvdl's Avatar
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    Quote Originally Posted by Mathstud28 View Post
    $\displaystyle \int {\frac{\1}{\sqrt{\lnx}}}\,dx}$ ?
    Try using this piece of LaTeX code instead:
    \int \frac{1}{\sqrt{ln x}} \ dx

    $\displaystyle \int \frac{1}{\sqrt{ln x}} \ dx$
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  3. #3
    MHF Contributor Mathstud28's Avatar
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    Thank you so much!

    I am having a hard time adapting to this haha
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  4. #4
    Math Engineering Student
    Krizalid's Avatar
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    It can't be integrated. May be $\displaystyle \int_0^1\frac1{\sqrt{-\ln x}}\,dx$ it's a good question.
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  5. #5
    MHF Contributor Mathstud28's Avatar
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    OH ok

    thank you
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  6. #6
    MHF Contributor Mathstud28's Avatar
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    What is the diffenrece

    I recognize that \int_0^1\frac1{\sqrt{-\ln x}}\,dx = $\displaystyle \Gamma$(1/2) but why does that make a differnece?
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  7. #7
    MHF Contributor Mathstud28's Avatar
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    Just to make sure I am understood.

    $\displaystyle \int_0^1\frac1{\sqrt{-\ln x}}\,dx$=$\displaystyle \Gamma$(-1/2)
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