$\displaystyle \int {\frac{\1}{\sqrt{\lnx}}}\,dx}$ ?
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Originally Posted by Mathstud28 $\displaystyle \int {\frac{\1}{\sqrt{\lnx}}}\,dx}$ ? Try using this piece of LaTeX code instead: \int \frac{1}{\sqrt{ln x}} \ dx $\displaystyle \int \frac{1}{\sqrt{ln x}} \ dx$
I am having a hard time adapting to this haha
It can't be integrated. May be $\displaystyle \int_0^1\frac1{\sqrt{-\ln x}}\,dx$ it's a good question.
thank you
I recognize that \int_0^1\frac1{\sqrt{-\ln x}}\,dx = $\displaystyle \Gamma$(1/2) but why does that make a differnece?
$\displaystyle \int_0^1\frac1{\sqrt{-\ln x}}\,dx$=$\displaystyle \Gamma$(-1/2)
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