# Help needed with algebra

• Apr 1st 2008, 11:46 AM
michaela-donnelly
Help needed with algebra
Hi

I've been trying out some exam questions but have become stuck on one and was hoping someone out there might be able to help me.

The question is:
Evaluate using the method of residues
$\int_{0}^{2\pi}\frac{\cos2\theta \: d\theta}{1-2acos\theta + a^2}$

So far I have that
$\int_{0}^{2\pi}\frac{\cos2\theta\:d\theta}{1-2acos\theta+a^2}$ = $\frac{1}{2i}\int\frac{z^4+1}{z^3(a^2-az-az^-1+1)}$

as $cos2\theta= \frac{(z^2+z^-2)}{2}$and $d\theta=\frac{dz}{iz}$

I've tried to multiply all of this out and tidy up but the algebra is causing me problems from this point on and I was hoping you might be able to tell me where I'm going wrong.

Any suggestions would be gratefully appreciated

Thanks
• Apr 1st 2008, 11:53 AM
ThePerfectHacker
What is $a$? What are the restictions on it? Is it $|a|<1$?
• Apr 1st 2008, 12:01 PM
Opalg
Quote:

Originally Posted by michaela-donnelly
$\int_{0}^{2\pi}\frac{\cos2\theta\:d\theta}{1-2acos\theta+a^2}$ = $\frac{1}{2i}\oint\frac{z^4+1}{z^3(a^2-az-az^{-1}+1)}dz$

The denominator factorises as $z^2(a-z)(az-1)$. The double pole at z=0 is obviously inside the contour. The other poles are at z=a and z=a^{-1}. One of these will be inside the contour and the other one outside (unless |a|=1, in which case you are in trouble).
• Apr 6th 2008, 09:04 AM
michaela-donnelly
Help needed with algebra
thank you for your reply. I don't know if there are any restrictions on a as the question doesn't say. I presume it is that $|a|<1$ but I'm not sure....