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Math Help - Logarithm problems

  1. #1
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    Logarithm problems

    Apologies for formatting!

    Find x:
    log x + log 5 = 1

    -> log (x * 5)
    -> log 5x
    -> 5^x = 1
    -> x = 0
    I dunno if this is right or not and I don't have any worked examples to help me along.

    My main problem is 2 log(base x) 2 = 1/3
    I don't know where to start with this.

    Thank you for any help ion advance.
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  2. #2
    Member javax's Avatar
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    Quote Originally Posted by Jamie88 View Post
    Apologies for formatting!

    Find x:
    log x + log 5 = 1

    -> log (x * 5)
    -> log 5x
    -> 5^x = 1
    -> x = 0
    I dunno if this is right or not and I don't have any worked examples to help me along.

    My main problem is 2 log(base x) 2 = 1/3
    I don't know where to start with this.

    Thank you for any help ion advance.
    5x=10, because the base of log is 10^1 = 10 then comes x = 2
    The second
    2log_x2 = \frac{1}{3}
    log_x2^2=\frac{1}{3}
    \frac{1}{log_4x}=\frac{1}{3}
    log_4x = 3
    x = 4^3
    x=64
    btw I think this isn't the place to post such a problems!
    Last edited by javax; April 1st 2008 at 07:45 AM.
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