# Thread: Logarithm problems

1. ## Logarithm problems

Apologies for formatting!

Find x:
log x + log 5 = 1

-> log (x * 5)
-> log 5x
-> 5^x = 1
-> x = 0
I dunno if this is right or not and I don't have any worked examples to help me along.

My main problem is 2 log(base x) 2 = 1/3
I don't know where to start with this.

Thank you for any help ion advance.

2. Originally Posted by Jamie88
Apologies for formatting!

Find x:
log x + log 5 = 1

-> log (x * 5)
-> log 5x
-> 5^x = 1
-> x = 0
I dunno if this is right or not and I don't have any worked examples to help me along.

My main problem is 2 log(base x) 2 = 1/3
I don't know where to start with this.

Thank you for any help ion advance.
5x=10, because the base of log is 10^1 = 10 then comes x = 2
The second
$\displaystyle 2log_x2 = \frac{1}{3}$
$\displaystyle log_x2^2=\frac{1}{3}$
$\displaystyle \frac{1}{log_4x}=\frac{1}{3}$
$\displaystyle log_4x = 3$
$\displaystyle x = 4^3$
$\displaystyle x=64$
btw I think this isn't the place to post such a problems!