how to integrate (4-x^2)^(-3/2)?
Could you explain this? I (no joke) thought to myself "What would Krizalid do?" and so I tried making it [(2+x)(2-x)]^(-3/2) and substituting a=2+x, but that got me [a(4+a)]^(-3/2) which didn't seem to get any simpler to me, so I went with this method. I want to see what you're talking about though, I find your methods helpful.