Ok I am drawing a blank

(e^(-x²))...from there I went to e^(-x²)≡ [(-x²)^n/n!]= [(-1)^n*x^(2n)/n!] so (e^(-x²))= [!]= [(-1)^n*x^(2n)/n!] dx]...but I am stuck on where to go from here if there is route

It should read (e^(-x²))= [(-1)^n*x^(2n)/n!] dx]...

Well it's just a direct application of Maclaurin series for

I've learned it but forgotten (Giggle) could you elaborate

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Originally Posted by Mathstud28

(e^(-x²))...from there I went to e^(-x²)≡ [(-x²)^n/n!]= [(-1)^n*x^(2n)/n!] so (e^(-x²))= [!]= [(-1)^n*x^(2n)/n!] dx]...but I am stuck on where to go from here if there is route

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but that holds true because n! and (-1)^n are constants and you just yanked them out evaluated your integral and then reintroduced them?