I was wondering the anit-derivative of (4x^2+2)x^-1 ? I think it's something along the lines of 2x^2+lnx^2+C. I know thats wrong and I can't seem to figure this out.
If what you mean what is $\displaystyle integral$(4x²-2)/x what you would do is break apart the integrand into 4x-2/x and from there you can see that it is 2x²+2ln|x|+C...but I dont think that is what you mean considering how easy that is...
Don't worry it happens to us all...once I integrated the (x²-a²)^(1/2) very young was so proud...but then got it wrong because I forgot +C lol...it happens to us all