# very important for me help

• Mar 31st 2008, 05:16 AM
botnaim
very important for me help
If a function is continous uniformely at [1, infinity)
does it mean that exist the limit f(x) in the wide sense? ( while x approaches infinity ).
if you take sqrt(x) the limit is infinity and yet its uniform continous.
but i can't find an example that contradicts the wide sense limit part? and I can't quite
manage to prove it.

I have a test tomorrow.
• Mar 31st 2008, 05:35 AM
colby2152
Quote:

Originally Posted by botnaim
If a function is continous uniformely at [1, infinity)
does it mean that exist the limit f(x) in the wide sense? ( while x approaches infinity ).
if you take sqrt(x) the limit is infinity and yet its uniform continous.
but i can't find an example that contradicts the wide sense limit part? and I can't quite
manage to prove it.

I have a test tomorrow.

If a function is continuous, it does not necessarily mean that a limit exists. Think about $\sin(x)$