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Math Help - Asymptote or not?

  1. #1
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    Asymptote or not?

    I haven't done maths in ages so my confidence is pretty low with I guess.

    Just a quick question...

    y = 3^x + 1

    x: -2 -1 0 1 2 3
    y=3^x+1: 1 1/9 1 1/3 1 4 10 28

    I was just wondering whether these values are correct or not because 1 1/3 is slightly larger than just 1 so it can't be an asymptote?
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  2. #2
    Bar0n janvdl's Avatar
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    Quote Originally Posted by Jamie88 View Post
    I haven't done maths in ages so my confidence is pretty low with I guess.

    Just a quick question...

    y = 3^x + 1

    x: -2 -1 0 1 2 3
    y=3^x+1: 1 1/9 1 1/3 1 4 10 28

    I was just wondering whether these values are correct or not because 1 1/3 is slightly larger than just 1 so it can't be an asymptote?
    Code:
    x:      -2      -1     0   1   2
    y:   1.1111   1.3333   2   4   10
    By looking at the function I cannot see any other asymptotes it might have, except for a horisontal asymptote y = 1
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  3. #3
    Bar0n janvdl's Avatar
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    By the way, it is a bit hard to make out your table, but it seems you think 3^0 = 0

    That is not true.

    Anything to the power zero is 1

    EXCEPT  0^0 which is undefined
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  4. #4
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    Ohhh thank you.

    I see where I went wrong now...

    I did 3^0 but forgot to +1 the 1 to get 2.

    Thank mate.
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  5. #5
    Bar0n janvdl's Avatar
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    Quote Originally Posted by Jamie88 View Post
    Ohhh thank you.

    I see where I went wrong now...

    I did 3^0 but forgot to +1 the 1 to get 2.

    Thank mate.
    You're welcome!
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