I couldn't seem to find a board on logarithms so apologised if this is in the incorrect section. Apologies for formatting too.
I'm trying to work out log 4^2x-1 = log 3^x+1
I've done this so far (but I think I've made it more difficult than it needs to be)
i) (2x – 1)log 4 = (x + 1)log 3
ii) 2x-1= (x+1)log3 / log4
iii) 2x - (x+1)log 3 / log 4 = 1
but I do not know where to go from there...and like I said I think there is an easier more straightforward way to do this.
I'd appreciate any help. Thank you.