hi, im unsure on how to solve a certain limit using the sandwhich rule. lim [(x-3) sin(1/(3-x))] as x -> 3 any help or hints would be much appreciated..thank you
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Originally Posted by tasukete hi, im unsure on how to solve a certain limit using the sandwhich rule. lim [(x-3) sin(1/(3-x))] as x -> 3 any help or hints would be much appreciated..thank you The limit can be re-written as where y = 3 - x. This in turn can be re-writen as where . Now read this.
just need to confirm something....if y = x - 3 wouldnt that make -y = 3-x ??? since u put: ysin(1/y) wouldnt it be: ysin(1/-y) instead? hope im right..
oops :O pls ignore my previous post...read it in such a rush didnt see the -ve sign ...sry =] . thank you for your help so far
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