Question given: newtons law of cooling is given by
(Θ=theta)
Θ=Θoe^-kt
where the excess of tempreature at 0 deg = Θo deg and the time T is Θ deg.
given that Θo=15 deg and K=-0.02 find the time when the rate of change of tempture is 1 deg
my work
1=15e^-0.02XT
i assume u must use log to rearence the forumla in oder to get a value then differentiate it to find the rate of change of T.
is what iv done so far correct?