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Math Help - Integrating this function

  1. #1
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    Integrating this function

    Hi all,

    How do I integrate

     \int \frac{dx}{(x^2 + y^2)^{3/2}}


    thanks
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  2. #2
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    Quote Originally Posted by kuntah View Post
    Hi all,

    How do I integrate

     \int \frac{dx}{(x^2 + y^2)^{3/2}}


    thanks
    In this y will be considered a constant, so first let
    x = y \cdot u implies dx = y~du
    or

    So
     \int \frac{dx}{(x^2 + y^2)^{3/2}} = \int \frac{y~du}{(y^2u^2 + y^2)^{3/2}}

    = \frac{1}{y^2} \int \frac{du}{(u^2 + 1)^{3/2}}

    Can you do this now?

    -Dan
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  3. #3
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    He thanks Dan
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