Hi,
I was wondering if anyone could help me solve or even know the type of the differential equation below
$\displaystyle d^2x/dt^2= k.dy/dt$
where k is a constant.
Thanks very much
Gareth
$\displaystyle \frac{d^2x}{dt^2} = k~\frac{dy}{dt}$
So
$\displaystyle \int \frac{d^2x}{dt^2}~dt = k \int \frac{dy}{dt}~dt$
$\displaystyle \frac{dx}{dt} = ky + C$
This is as far as we can go unless you want to put the solution in integral form:
$\displaystyle \int \frac{dx}{dt}~dt = k \int y(t)~dt + Ct$
$\displaystyle x(t) = k \int y(t)~dt + Ct + A$
-Dan