I have worked this problem over but still can not get a reasonable answer. I would like some help, please.
I am given the parametric equations: x=e^t and y=(1/3)e^3t. I am to revolve the resulting shape around the x-axis and calculate the surface area. I know that I must use
2*pi*the radius*sqrt((dx/dt)^2 + (dy/dt)^2)
in order to find the surface area. However, I'm not sure what my radius is and the integral is difficult because of the tricks it needs.
I could really use some assistance ASAP.