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Math Help - Calc derivative

  1. #1
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    Calc derivative

    A patient's temperature change, T, due to a dose, D, of a drug is given by the following equation. C is a positive constant.
    T = (C/2-D/3)D^2

    If the sensitivity of the body to the drug is defined by dT/dD, what dosage maximizes sensitivity?
    D=


    does that mean just find the derivative and solve for D?
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  2. #2
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    Quote Originally Posted by bluejewballs View Post
    A patient's temperature change, T, due to a dose, D, of a drug is given by the following equation. C is a positive constant.
    T = (C/2-D/3)D^2

    If the sensitivity of the body to the drug is defined by dT/dD, what dosage maximizes sensitivity?
    D=


    does that mean just find the derivative and solve for D?
    Hello,

    Yep, derivate by D, and find D so as to annulate the derivate, meaning that the value will be a minimum or a maximum (or a particular point). You should study the behaviour of the function =)
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  3. #3
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    T is y, D is x, C is just a constant

    so lets write this question as y = (c/2 - x/3)x^2

    Does that make things easier?

    -Andy
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