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Thread: Series

  1. March 24th 2008, 11:53 AM #1
    Silver
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    Series

    \sum_{r=1}^{20} \frac{1}{(r+3)(r+6)}

    Help, please?
    I'll never understand Series.
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  2. March 24th 2008, 12:02 PM #2
    ThePerfectHacker
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    \frac{1}{(k+3)(k+6)} = \frac{1}{3}\left( \frac{ 1 }{k+3} - \frac{1}{k+6}\right).
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  3. March 24th 2008, 09:17 PM #3
    mr fantastic
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    Quote Originally Posted by Silver View Post
    \sum_{r=1}^{20} \frac{1}{(r+3)(r+6)}

    Help, please?
    I'll never understand Series.
    If you're still stuck after reading TPH's reply, read Telescoping series - Wikipedia, the free encyclopedia
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