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Math Help - on the graph of y=2e^x are drawn the tangent and normal to the curve at the pt.G(p,q)

  1. #1
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    Smile on the graph of y=2e^x are drawn the tangent and normal to the curve at the pt.G(p,q)

    on the graph of y=2e^x are drawn the tangent and normal to the curve at the pt.G(p,q)

    a) Find the gradient of the tangent at G in terms of q.
    b) Find the equation of the tangetn and normal to the curve at point G

    I think i have the right answers for these, but when i go to part c is doesn't seem to work/gets messy.
    the answers i have are
    a) q=2e^p
    b) tangent= 2xe^p-2pe^p + q
    and normal= -x/2e^p + p/2e^p+ q

    Uploaded is a picture of the graph with the tangent and normal.

    I also have to find out the co-ordinates of the points A, B, C, D,E and F in terms of p and q. I have worked out B and E but i have no idea how to even begin wiht the others.

    I dont necessarily want the answer, just a way in which to do it.
    Cheers.
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  2. #2
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    You didn't upload the image. Mind doing that for us? Your part a and b looks fine to me.
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  3. #3
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    Sorry, must've forgotten

    here it is.
    Attached Thumbnails Attached Thumbnails on the graph of y=2e^x are drawn the tangent and normal to the curve at the pt.G(p,q)-maths-q.bmp  
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  4. #4
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    I'm not sure what E and B are referring to but it looks like they're the same point as G?

    F is the y-intercept of your normal line. From your pre-calculus days, what do you do to find it? Similarly, C is your x-intercept.

    D is the y-intercept of your tangent line and A is its x-intercept.
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  5. #5
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    Smile

    ah k thanks lol thats kinda obvious now u pointed it out :P

    thanks heaps
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