Could anybody please point me in the right direction with this inverse laplace transform?
L-1 {(e^(-0.165s)) / ((1+0.63s)s)
i think its a heaviside function
so H(t-a)= H(t-0.165)
which leaves me with
1 / ((1+0.63s)s)
and this where i'm stuck (No doubt the solution is staring me in the face!)
I thought this one looked simple but i was wrong again!
I've split it down into the partial fractions
A/s + B/(bs+1)
so
1=A(bs+1) + Bs
let S=0
A=1
expanding the equation
1=Abs+A+Bs
equating the coefficients
0=Ab+B
as A=1
then B=-b
i think this is right so far (but i'm often wrong )
this leaves me with the following to transform
(L-1) 1/s - b/(bs+1)
or
(L-1) 1/s - 1/(s-(-1/b))
= 1- e^-((1/b)t)
is this near the mark?