1. Differential Equations

Find the function u(t) from the differential equation and the initial condition.
du/dt= e^(1t-3.2u) u(0) = 2.6

u(t) =

2. Originally Posted by BKennedy
Find the function u(t) from the differential equation and the initial condition.
du/dt= e^(1t-3.2u) u(0) = 2.6

u(t) =
This is separable:
$e^{3.2u}~du = e^t~dt$

So integrate both sides and apply your initial condition.

-Dan