Find the function u(t) from the differential equation and the initial condition. du/dt= e^(1t-3.2u) u(0) = 2.6 u(t) =
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Originally Posted by BKennedy Find the function u(t) from the differential equation and the initial condition. du/dt= e^(1t-3.2u) u(0) = 2.6 u(t) = This is separable: $\displaystyle e^{3.2u}~du = e^t~dt$ So integrate both sides and apply your initial condition. -Dan
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