solve the differential equation, subject to given condition

(x^2)(y')+1/y^2=0 , y(1)=2

any help would be appreciated. thanks!

i ended up with -x^-2=y^3 and im stuck but im pretty sure im doing it wrong =/

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- Mar 19th 2008, 01:44 PMs0urgrapeshelp with integration (differential equations)
solve the differential equation, subject to given condition

(x^2)(y')+1/y^2=0 , y(1)=2

any help would be appreciated. thanks!

i ended up with -x^-2=y^3 and im stuck but im pretty sure im doing it wrong =/ - Mar 19th 2008, 02:16 PMSoroban
Hello, s0urgrapes!

Quote:

Solve the differential equation, subject to given condition

. .

Separate variables: .

Integrate: .

From , we have: .

Therefore: .

- Mar 19th 2008, 02:26 PMs0urgrapes
wow thanks alot

i think the mistake i made was making the -2 into a -3 while integrating instead of -1 like it should be