does anybody know the inverse laplace transform of (5+s)/(s^2 +2s) , to revert to a function of t again....

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- March 19th 2008, 07:32 AMjohnbarkwithinverse laplace transform
does anybody know the inverse laplace transform of (5+s)/(s^2 +2s) , to revert to a function of t again....

- March 19th 2008, 08:09 AMPeritus
partial fraction expansion:

I'll assume that you'll be able to find the constants a and b.

Now all we need to do is look at the transform table (I'll assume that the TF is casual) :

... - March 19th 2008, 09:37 AMjohnbarkwith
is that meant to be 5/s(s+2) + 1/s+2

- March 29th 2008, 11:41 PMDanshader
(5+s)/(s^2 + 2s)

= 5/(s^2 + 2s) + s/(s^2 + 2s)

= 5/s(s + 2) + s/s(s + 2)

= 5/s(s + 2) + 1/(s + 2)

applying partial fraction to the first term we get,

= 5/2s -5/2(s+2) + 1/(s+2)

applying inverse Laplace transform (using the table)

=5/2 -5 exp(-2t)/2 + exp(-2t)