hi guys

just a quick check to make sure im getting this right

$\displaystyle h(x)=f(g(x))$

where $\displaystyle f(x) = x^5$ and $\displaystyle g(x)=x^2+1$

so $\displaystyle h(x)=(x^2+1)^5$

$\displaystyle h'(x)=5(x^2+1)^4(2x)$ <---- heheh everyone noticed the type. Yes i meant h not f XD

now heres the part that confuses me. Is it correct to multiply the 5 before the brackets by the 2x to get

$\displaystyle 10x(x^2+1)^4$?

Help appreciated