Thread: Please check my answers

determine if it exists Lim x^2-2x+1/sqrt(x+3)-2
x->1

Lim x^2-2x+1 *sqrt(x+3 ) +2 / (sqrt(x+3)-2)(sqrt(x+3)+2)
x->1

Lim (x-1)(x-1)*sqrt(x+3 ) +2 /(x-1)
x->1

Lim (x-1) sqrt(x+3 ) +2 = 0
x->1

Originally Posted by bobby77

determine if it exists Lim x^2-2x+1/sqrt(x+3)-2
x->1

Lim x^2-2x+1 *sqrt(x+3 ) +2 / (sqrt(x+3)-2)(sqrt(x+3)+2)
x->1

Lim (x-1)(x-1)*sqrt(x+3 ) +2 /(x-1)
x->1

Lim (x-1) sqrt(x+3 ) +2 = 0
x->1

Hello,

please use brackets to determine numerator and denominator of fractions. Otherwise your terms are not clear enough to help you.

Greetings

EB

determine if it exists Lim (x^2-2x+1)/(sqrt(x+3)-2)
x->1

Lim (x^2-2x+1) *(sqrt(x+3 ) +2) /[ (sqrt(x+3)-2)(sqrt(x+3)+2) ]
x->1

Lim [(x-1)(x-1)]*(sqrt(x+3 ) +2) /(x-1)
x->1

Lim (x-1)*( sqrt(x+3 ) +2) = 0
x->1

Originally Posted by bobby77

determine if it exists Lim (x^2-2x+1)/(sqrt(x+3)-2)
x->1

Lim (x^2-2x+1) *(sqrt(x+3 ) +2) /[ (sqrt(x+3)-2)(sqrt(x+3)+2) ]
x->1

Lim [(x-1)(x-1)]*(sqrt(x+3 ) +2) /(x-1)
x->1

Lim (x-1)*( sqrt(x+3 ) +2) = 0
x->1

Or more simply ya got,

Rationalize,

Thus,

Thus,

As, you get 0.