Results 1 to 4 of 4

Math Help - Part of an Indefinite Integral Problem

  1. #1
    !!!
    !!! is offline
    Junior Member
    Joined
    Feb 2008
    Posts
    28

    Part of an Indefinite Integral Problem

    How do I get from the left side of this equation to the right?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Junior Member roy_zhang's Avatar
    Joined
    Mar 2008
    Posts
    64
    It looks like just applying the quotient rule.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    !!!
    !!! is offline
    Junior Member
    Joined
    Feb 2008
    Posts
    28
    Sorry, I should have added more detail to my first post. I know that I should apply the quotient rule, but my answer keeps differing from the correct one above. Can somebody please show the the work so I know what I'm doing wrong?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Junior Member roy_zhang's Avatar
    Joined
    Mar 2008
    Posts
    64
    Ok, let's see.

    \frac{d}{dx}[\frac{\sqrt{x^2+a^2}}{x}]=\frac{(x)\frac{d}{dx}[\sqrt{x^2+a^2}]-\sqrt{x^2+a^2}(\frac{d}{dx}x)}{x^2}
    =\frac{(x)[\frac{1}{2}(x^2+a^2)^{(-\frac{1}{2})}(2x)]-\sqrt{x^2+a^2}\cdot 1}{x^2}=\frac{x(\frac{x}{\sqrt{x^2+a^2}})-\sqrt{x^2+a^2}\cdot 1}{x^2}

    Then multiply the fraction with the coefficient -\frac{1}{a^2}, you will have the desired result.


    Roy
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. need help with indefinite integral problem
    Posted in the Calculus Forum
    Replies: 2
    Last Post: October 23rd 2011, 11:07 PM
  2. indefinite integral problem
    Posted in the Calculus Forum
    Replies: 5
    Last Post: June 28th 2011, 03:53 AM
  3. Find the Indefinite Integral part b
    Posted in the Calculus Forum
    Replies: 2
    Last Post: September 12th 2010, 02:31 PM
  4. Indefinite Integral Problem
    Posted in the Calculus Forum
    Replies: 3
    Last Post: January 19th 2010, 07:11 AM
  5. Indefinite Integral Problem Please
    Posted in the Calculus Forum
    Replies: 1
    Last Post: December 4th 2007, 08:11 PM

Search Tags


/mathhelpforum @mathhelpforum