Hello just need som tips on how to integrate this x/(1-x^2)^1,5 thanks
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$\displaystyle \int\frac{x}{\sqrt{1-x^{2}}}dx$ Let $\displaystyle u=1-x^{2}, \;\ du=-2xdx, \;\ \frac{-1}{2}du=xdx$ Then, you get: $\displaystyle \frac{-1}{2}\int\frac{1}{\sqrt{u}}du$ Now, integrate and resub.
Hello, Hem...this is 1.5, right or not ?
Originally Posted by Moo Hem...this is 1.5, right or not ? That doesn't matter, one can even compute a more general integral like $\displaystyle \int {\frac{x} {{\left( {1 - x^2 } \right)^n }}\,dx},$ and its result follows from galactus' procedure.
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