integrate 1 / (3-2x)^2. i dont understand how to integrate in this format, can someone please help me?
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o__O Take t=3-2x
Hi, Or make appear the derivate of (3-2x) above, and you'll get u'(x)/uČ(x), and its integrate is -1/u
Originally Posted by -sonal- integrate 1 / (3-2x)^2. i dont understand how to integrate in this format, can someone please help me?
Nacho's answer is correct, but Originally Posted by Nacho double implies it's applied when having equality, like So in this case we require an equal sign.
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