If dy/dx = xy - y^2 and y(1) = 3, then y(2) is ?
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Originally Posted by DINOCALC09 If dy/dx = xy - y^2 and y(1) = 3, then y(2) is ? Re-arrange into $\displaystyle \frac{dy}{dx} - x y = -y^2$ and it's clearly a Bernoulii differential equation with n = 2, $\displaystyle P(x) = -x$ and $\displaystyle Q(x) = -1$ ......
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