I understand all the steps in solving the problem except for the final answer.
Y= (-2t^2+1) / (3t^2-5)
I know that f (t) * g' (t) = (-12t^3+6t)
g (t) * f' (t) = (-12t^3+20t)
y= (14/3t^2-5)^2 (answer)
I know that the denominator is always gonna be the second part of the equation squared. But how in the heck do you get the 14?
Thanks for all the help Peace