I understand all the steps in solving the problem except for the final answer.

Y= (-2t^2+1) / (3t^2-5)

I know that f (t) * g' (t) = (-12t^3+6t)

g (t) * f' (t) = (-12t^3+20t)

y= (14/3t^2-5)^2(answer)

I know that the denominator is always gonna be the second part of the equation squared.But how in the heck do you get the 14?

Thanks for all the help Peace