Use the method of cylindrical shells to find the volume of the solid obtained by rotating the region bounded by y = 6sqrt(x) and y = 6x^2 about the y axis.

I keep getting ~9.425 which is wrong, but I'm not sure why yet!

Here is how I come to my answer time and time again...

S = integral sign loL

V = S 2pi(x(6sqrt(x) - 6x^2))

V = 2pi S (6x - 6x^3)

V = 2pi [3x^2 - (3/2)x^4] from 0-1

V = 9.4248