Hi, I need help integrating this equation; dv/dt=(-g/b^2)(v^2+b^2) This is causing me problems. I'd really appreciate a solution/pointer Thanks Jem
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Originally Posted by jemmy Hi, I need help integrating this equation; dv/dt=(-g/b^2)(v^2+b^2) $\displaystyle v' = (-g/b^2)(v^2+b^2)\implies \frac{v'}{v^2+b^2} = - gb^2$. Thus, $\displaystyle \int \frac{v'dt}{v^2+b^2} = -\int -gb^2 dt \implies \frac 1b\tan^{-1} \frac{v}{b} + C = -gb^2t$ (assuming b>0).
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