need to get the integral of: 3x - x/((x^2+2)^4/3) substitution rule here? or is it ln. i'm not sure
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Hello, You can integer 3x on its own. For the second term, you can rewrite it into is , 2x is the derivate of x² With all that elements you should be able to find the integral, using only formulas you learnt
i dont understand that at all.. i'm new to integrals.. can you show me how to do it directly sorry
Originally Posted by s0urgrapes need to get the integral of: 3x - x/((x^2+2)^4/3) substitution rule here? or is it ln. i'm not sure To integrate , make the substitution . Note that . So Remember to substitute back at the finish ....
Ok... First of all, note the formulas you should know : The integral of is We have here The integral of 3x is 3x²/2 In the second term, u(x)=x²+2. u'(x)=2x. n=-4/3, so n+1 will be -1/3 and 1/(n+1) will be -3 Hence the integral is :
thanks!
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