# Math Help - Improper Integrals - need help

1. ## Improper Integrals - need help

need help on this:

as you can tell the top one is the question, and the bottom 1 shows how to do it. however, the problem is i cant figure how to solve it. when i put it in my ti-83, it gives me about 2.303, but its wrong. i need help on wut to do after u get ln(n) - ln(1).
thx

2. Just take the limit as n ---> infinity.

ln(1)=0, so all you have to deal with is $\lim_{n\rightarrow{\infty}}ln(n)$

It should be rather obvious what the limit is.

A TI-83 isn't the best for integration. Get a TI-89.