Find the location of the indicated absolute extremum within the specified domain.
Maximum of f(x) = x^2 - 4 ; [-1, 2]
f'(x) = 2x
f'(x) = 0
2x = 0 => x = 0 ( what extremum is this?)
f(x) = x^2 - 4
f(-1)= 1 - 4 => f(-1) = - 3 (what extremum is this?)
f(2)= 4 - 4 => f(2) = 0 (what extremum is this?)
( and also do i have it done right?)
( Lial, Greenwell & Ritchey) and trying to do some of it. Very sorry because i took some of Your time with my questions, for 2 weeks how long I have been member i learn a lot ( also get banned because i put 3 times same thing, didnt know for that rule also sorry for that It was my faul)
Anyway want to say Thank You to all of You.
Let me answer Your question: I really can not remember a lot about graphs and parabolas. When i finish "my personal homework" probably will start learning graphs.