Find the derivative of the function g(t) = cosh^3(t). ok, so i know the correct answer for this one: 3cosh^2(t)sinh(t) now i would like someone to show me how exactly to get that answer... thanks mathlete
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Let We can write it as, where and . Simply use the chain rule. Chain rule:
Originally Posted by wingless Let We can write it as, where and . Simply use the chain rule. Chain rule: oh ok, so the derivative of cosh(t) is just sinh(t), thats what i was having trouble with, but i guess its easier than i was making it... thanks
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