Find the derivative of the function g(t) = cosh^3(t).

ok, so i know the correct answer for this one:

3cosh^2(t)sinh(t)

now i would like someone to show me how exactly to get that answer...

thanks

mathlete

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- Mar 11th 2008, 09:18 AMmathletehyperbolic functions!!
Find the derivative of the function g(t) = cosh^3(t).

ok, so i know the correct answer for this one:

3cosh^2(t)sinh(t)

now i would like someone to show me how exactly to get that answer...

thanks

mathlete - Mar 11th 2008, 09:44 AMwingless
Let $\displaystyle h(t) = \cosh^3 t$

We can write it as,

$\displaystyle f(g(t))$ where $\displaystyle f(t) = t^3$ and $\displaystyle g(t) = \cosh t$.

Simply use the chain rule.

Chain rule:

$\displaystyle [f(g(t))]' = f'(g(t))\cdot g'(t)$ - Mar 11th 2008, 10:29 AMmathlete